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A side-by-side comparison of 10U and 12U baseball pitching techniques. See the differences in form, power, and skill! ‘Trump Has No Authority’: Fallout at Federal Reserve Putin ally issues dire ...
Understanding the Context
A consequence of this behavior is that when you add 10 to - 10u, the result is "one greater than the largest value that can be represented by the resulting type", so it gets truncated to zero. This is exactly the behavior that you get when adding +10 and -10 using a signed type. Perhaps this behavior is easier to understand with decimals. 10 is a signed int.
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10U is an unsigned int. So maybe you are doing this to avoid implicit type conversions. In most scenarios, though (and in the example you posted, for sure), the implicit type conversions would work perfectly anyway. But if there's a way to avoid them, what harm is there in doing so? I'm just guessing.
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In function 'int main()': 37:20: warning: iteration 10u invokes undefined behavior [-Waggressive-loop-optimizations] 30:3: note: containing loop I don't understand why xor ing the M[i] and k causes the warning, if you comment in the line 52, the warning disappears. EDIT Similarly, the code when compiled with g++ throws the similar warning.